-.0002x^2+2.487x+2=0

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Solution for -.0002x^2+2.487x+2=0 equation: 



-.0002x^2+2.487x+2=0

We add all the numbers together, and all the variables

-0.0002x^2+2.487x+2=0

a = -0.0002; b = 2.487; c = +2;
Δ = b2-4ac
Δ = 2.4872-4·(-0.0002)·2
Δ = 6.186769
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.487)-\sqrt{6.186769}}{2*-0.0002}=\frac{-2.487-\sqrt{6.186769}}{-0.0004}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.487)+\sqrt{6.186769}}{2*-0.0002}=\frac{-2.487+\sqrt{6.186769}}{-0.0004}
$

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